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Implement regular expression matching with support for '.'
and '*'
.
'.' Matches any single character.'*' Matches zero or more of the preceding element.The matching should cover the entire input string (not partial).The function prototype should be:bool isMatch(const char *s, const char *p)Some examples:isMatch("aa","a") → falseisMatch("aa","aa") → trueisMatch("aaa","aa") → falseisMatch("aa", "a*") → trueisMatch("aa", ".*") → trueisMatch("ab", ".*") → trueisMatch("aab", "c*a*b") → true
代码如下
class Solution {public: bool isMatch(const char *s, const char *p) { if(*p == '\0') return *s == '\0'; if(*(p+1) != '*'){ if((*p==*s) || ((*p=='.') && (*s!='\0'))) return isMatch(s+1, p+1); else return false; }else{ while(*s && (*s==*p || *p=='.')) { if(isMatch(s, p+2)) return true; s++; } return isMatch(s, p+2); } return false; }};
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